Definitions related to the Rational Numbers – Chapter 3:
Natural numbers (N): The counting numbers {1, 2, 3, …}, are called natural numbers. Some authors include 0, so that the natural numbers are {0, 1, 2, 3, …}.
Whole numbers(W): The numbers {0, 1, 2, 3, …}.
Integers (Z): Positive and negative counting numbers, as well as zero:{…, 2, 1, 0, 1, 2,…}.
Rational numbers (Q): Numbers that can be expressed as a ratio of an integer to a nonzero integer. All integers are rational, but the converse is not true.
Real numbers (R): Numbers that have decimal representations that have a finite or infinite sequence of digits to the right of the decimal point. All rational numbers are real, but the converse is not true.
For all natural numbers m, n and p the following hold.
m + n = n + m (Commutative property of addition)
m + (n + p) = (m + n) + p (Associative property of addition)
m x n = n x m (Commutative property of multiplication)
m x (n x p) = (m x n) x p (Associative property of multiplication)
m x (n + p) = (m x n) + (m x p) (distributive property)
Every nonempty subset of natural numbers of N (or W) has the smallest element.
This is called the well ordering property of natural numbers.
We know, the set of all Positive and negative counting numbers, as well as zero:{…, 2, 1, 0, 1, 2,…}. is called whole numbers. Denoted by Z. If m and n are two whole numbers, with the extension of addition and multiplication, we have to following properties:
 Closure property: for all integers a, b, both a + b and b + a also integers;
 Commutative property: for all integers a, b
a + b = b + a
a x b = b x a
 Associative property: for all integers a, b, c
a + (b + c) = (a + b) + c
a x (b x c) = (a x b) x c
 Distributive property: for all integers a, b, c
a x (b + c) = (a x b) + (a x c)
 Cancellation law: if a, b, c are integers such that, c ≠ 0 and ac = bc
Then a = b.
Rational Numbers – Chapter 3 – EXERCISE 1.3.1

Identify the property in the following statements:
(i) 2+(3+4)=(2+3)+4
Solution:
Associative property of addition
(ii) 2.8 = 8.2
Solution:
Commutative property of multiplication.
(iii) 8.(6+5)=(8.6)+(8.5)
Solution:
Distributive property

Find the additive inverses of the following integers:
(i) 6
Solution:
(6) is the additive inverse of 6.
(ii) 9
Solution:
(9) is the additive inverse of 9.
(iii) 123
Solution: (123) is the additive inverse of 123.
(iv) 76
Solution:
76 is the additive inverse of 76.
(v) 85
Solution:
85 is the additive inverse of 85.
(vi) 1000
Solution:
(1000) is the additive inverse of 1000.

Find the integer m in the following:
(i) m + 6 = 8
Solution:
m = 8 – 6
Thus, m = 2
(ii) m + 25 = 15
Solution:
m = 15 – 25
Thus, m = 10
(iii) m – 40 = 26
Solution:
m = 26 – 40
Thus, m = + 14
(iv) m + 28 = 49
Solution:
m = 49 28
Thus, m = 77
 Write in the following in increasing order:
21,8, 26, 85, 38, 333, 210, 0, 2011
Solution:
333, 210, 26, 8, 0, 21, 33, 85, 2011

Write the following in decreasing order: 85, 210, 58, 2011, 1024, 528, 364, 10000, 12
Solution:
2011, 528, 364, 210, 85, 12, 58, 1024, 10000
1.3.2 Rational numbers
Rational numbers (Q): Numbers that can be expressed as a ratio of an integer to a nonzero integer. All integers are rational, but the converse is not true.
Clearly, the numbers of the form p/q, where p and q are natural numbers.
Example 1: Add and multiply 1/3 and 8/5
Solution:
^{ 1}/_{3 +}^{ 8}/_{5 = }^{(5+8×3)}/_{15 }= ^{(5+24)}/_{15 }= ^{29}/_{15}
_{Their product is,}
^{1}/_{3}^{ x 8}/_{5 = }^{(1×8)}/_{15 }= ^{(8)}/_{15 }= ^{8}/_{15}
_{ }
Rational Numbers – Chapter 3 – EXERCISE 1.3.2
 Write down ten rational numbers which are equivalent to 𝟓/𝟕 and the denominator not exceeding 80.
Solution:
^{5}/_{7 }x^{ 2}/_{2 = }^{10}/_{14 }
^{5}/_{7 }x^{ 3}/_{3 = }^{15}/_{21}
^{5}/_{7 }x^{ 4}/_{4 = }^{20}/_{28}
^{5}/_{7 }x^{ 5}/_{5 = }^{25}/_{35}
^{5}/_{7 }x^{ 6}/_{6 = }^{30}/_{42 }
^{5}/_{7 }x^{ 7}/_{7 = }^{35}/_{49}
^{5}/_{7 }x^{ 8}/_{8 = }^{40}/_{56}
^{5}/_{7 }x^{ 9}/_{9 = }^{45}/_{63 }
^{5}/_{7 }x^{ 10}/_{10 = }^{50}/_{70}
^{5}/_{7 }x^{ 11}/_{11 = }^{55}/_{77 }
 Write down 15 rational numbers which are equivalent to and the numerator not exceeding 180.
Solution:
^{11}/_{5 }x^{ 2}/_{2 = }^{22}/_{10 }
^{11}/_{5 }x^{ 3}/_{3 = }^{33}/_{15}
^{11}/_{5 }x^{ 4}/_{4 = }^{44}/_{20}
^{11}/_{5 }x^{ 5}/_{5 = }^{55}/_{25}
^{11}/_{5 }x^{ 6}/_{6 = }^{66}/_{30 }
^{11}/_{5 }x^{ 7}/_{7 = }^{77}/_{35}
^{11}/_{5 }x^{ 8}/_{8 = }^{88}/_{40}
^{11}/_{5 }x^{ 9}/_{9 = }^{99}/_{45 }
^{11}/_{5 }x^{ 10}/_{10 = }^{110}/_{50}
^{11}/_{5 }x^{ 11}/_{11 = }^{121}/_{55 }
^{11}/_{5 }x^{ 12}/_{12 = }^{132}/_{60}
^{11}/_{5 }x^{ 13}/_{13 = }^{143}/_{65 }
^{11}/_{5 }x^{ 14}/_{14 = }^{154}/_{70 }
^{11}/_{5 }x^{ 15}/_{15 = }^{165}/_{75 }
^{11}/_{5 }x^{ 16}/_{16 = }^{176}/_{80 }
 Write down the ten positive numbers such that the sum of numerator and denominator of each is 11. Write them in decreasing order.
Solution:
Number:
^{10}/_{1},^{9}/_{2}, ^{8}/_{3},^{ 7}/_{4},^{ 6}/_{5},^{5}/_{6}, ^{4}/_{7},^{ 3}/_{8},^{2}/_{9}, ^{1}/_{10}
Decreasing order:
^{10}/_{1},^{9}/_{2}, ^{8}/_{3},^{ 7}/_{4},^{ 6}/_{5},^{5}/_{6}, ^{4}/_{7},^{ 3}/_{8},^{2}/_{9}, ^{1}/_{10}
 Write down the ten positive numbers such that the numerator and denominator for each them is 2. Write them in increasing order.
Solution:
^{Increasing order:}
^{1}/_{3},^{2}/_{4}, ^{3}/_{5 },^{ 4}/_{6},^{ 5}/_{7},^{6}/_{8}, ^{7}/_{9},^{ 8}/_{10},^{9}/_{11}, ^{10}/_{12}
 Is ^{3}/_{(2) }a rational number? If so, how do you write it in a form conforming to the definition of a rational number (that is, the denominator as a positive integer)?
Solution:
^{3}/_{(2) } is a rational number. It should be written as ^{3}/_{2 } to be rational number.
 Earlier you have studied decimals 0.9,0.8. Can you write these as rational numbers?
Solution:
Yes, we can write decimals like 0.9, 0.8 as rational numbers. i.e.,
0.9 = ^{9}/_{10 } and 0.8 = ^{8}/_{10}
1.3.3 Properties of rational numbers
Closure property:
We have learnt earlier, that, for all integers a, b, both a + b and b + a also integers;
Example1: Let us find the sum of ^{5}/_{6 }and ^{11}/_{13 }
Solution:
^{5}/_{6} + ^{11}/_{13} = ^{[(5×13)+(11×6)]}/_{(6×13)}
= ^{(65+66)}/_{78}
= ^{131}/_{78}
Example 2: The product of ^{2}/_{11 }and ^{8}/_{7 }:
Solution:
^{2}/_{11} + ^{8}/_{7 }= ^{(2×8)}/_{(11×7)}
= ^{16}/_{77}
The set of all rational numbers is closed under addition and multiplication.
Associative property:
We have learnt earlier, that, the associative property is, for all integers a, b, c
a + (b + c) = (a + b) + c
a x (b x c) = (a x b) x c
Example 3: Consider three rational numbers ^{1}/_{2 }, ^{4}/_{5 }, ^{6}/_{7 }
Solution:
^{1}/_{2 }+( ^{4}/_{5 }+ ^{6}/_{7}) = ^{1}/_{2 }+( ^{(1×5+4×2)}/_{(5×7)})
= ^{1}/_{2 }+ (^{2}/_{35 })_{ }
= ^{(35×1+(2)x2)}/_{(35×2) }
= ^{31}/_{70}
_{On the other hand,}
(^{1}/_{2 }+ ^{4}/_{5}) + ^{(6)}/_{7} = ^{(1×5+4×2)}/_{(2×5) }+ ^{(6)}/_{7}
= ^{(13)}/_{(10) }+ ^{(6)}/_{7}
= ^{[13×7+(6)x10]}/_{(10×7) }
= ^{31}/_{70}
Similarly, we can find for multiplication.
Thus, we can come to the conclusion that,
Addition and multiplication are associative on the set of all rational numbers.
Commutative property
We have learnt earlier, that, the commutative property is, for all integers a, b
a + b = b + a
a x b = b x a
Example 4: Let us take two rational numbers, say ^{8}/_{11 }and ^{(16)}/_{9 }
Solution:
^{8}/_{11} + ^{(16)}/_{9} = ^{(8×9+(16)x11)}/_{99 } _{ } _{ }
= ^{72176}/_{99 }
= ^{104}/_{99}
On the other hand,
^{(16)}/_{9} + ^{8}/_{11} = ^{((16)x11+8×9)}/_{99 } _{ } _{ }
= ^{176+72}/_{99 }
= ^{104}/_{99}
Example 5: Similarly, we can verify that,
^{8}/_{11} x ^{(16)}/_{9} = ^{(16)}/_{9} x ^{8}/_{11}
Addition and multiplication are commutative on the set of all rational numbers.
Distributive property
We have studied earlier, that, distributive property is, for all integers a, b, c
a x (b + c) = (a x b) + (a x c)
Consider the rational numbers, ^{3}/_{2}, ^{1}/_{2} and ^{1}/_{9}. Observe that,
^{3}/_{2 }x ( ^{1}/_{2 }+ ^{1}/_{9}) = ^{3}/_{2 }x ( ^{11}/_{18 }) = ^{22}/_{54} = ^{11}/_{27}
(^{3}/_{2 }x ^{1}/_{2 }) + ( ^{3}/_{2 }x ^{1}/_{9}) = (^{2}/_{6 }) + ( ^{2}/_{27 }) = ^{11}/_{27 }
In the set of all rational numbers, multiplication is distributive over addition.
Additive identity
Consider the rational number ^{0}/_{1}, observe that,
^{7}/_{8 }+ ^{0}/_{1} = ^{(7×1+0x8)}/_{8} = ^{7}
^{0}/_{1} + ^{7}/_{8} = ^{(0+7)}/_{8} = ^{7}/_{8}
_{Thus, the rational number }^{0}/_{1 acts as additive }identity. We denote this by 0.
The set of all rational numbers has 0 as additive identity; that is r + 0 = 0 + r = r, for all rational numbers.
Multiplicative identity
Again consider, the rational number, ^{1}/_{1}. We have, for example,
^{11}/_{12} x ^{1}/_{1} = ^{11}/_{12}
^{1}/_{1} x ^{11}/_{12} = ^{11}/_{12}
Thus, the rational number ^{1}/_{1 } is identity with respect to multiplication.
The set of all rational numbers has 1 as multiplicative identity, that is r x 1 = 1 x r = r, for all rational numbers.
Additive inverse
Take ^{8}/_{13 and }^{8}/_{13}. If we add these two, we get
^{8}/_{13} + ^{(8)}/_{13} = ^{(88)}/_{13} = ^{0}/_{13} = 0.
This is true for all rational numbers.
For each rational number r, there exists a rational number, denoted by – r, such that r + (r) = 0 = (r) + r.
Multiplicative inverse
We have studied earlier about multiplication inverse. Consider a rational number, ^{7}/_{5} , we see that,
^{7}/_{5} + ^{5}/_{7} = ^{35}/_{35} = 1
This is true for all rational numbers.
For each rational number r ≠ 0, there exists a rational number, denoted by r^{1} (or r x r^{1 }= r^{1} x r = 1
The only fundamental operations are addition and multiplication. The subtraction and division are defined in terms of addition and multiplication.
Rational Numbers – Chapter 3 – EXERCISE 1.3.3
 Name the property indicated in the following:
(i) 315+115 = 430
Solution:
Closure property of addition
(ii) ^{3}/_{4 }+ ^{9}/_{5} = ^{27}/_{20}
Solution:
Closure property of multiplication
(iii) 5 + 0 = 0 + 5 = 5
Solution:
0 is the additive identity
(iv) ^{8}/_{9} x 1 = ^{8}/_{9}
Solution:
1 is the multiplicative identity
(v) ^{8}/_{17} + ^{8}/_{17 }= 0
Solution:
Additive inverse
(vi)^{ 22}/_{23 }+ ^{22}/_{23} = 1_{ }
Solution:
Multiplication inverse
 Check the commutative property of addition for the following pairs:
(i)^{ 102}/_{201 },^{ 3}/_{4}
Solution:
We know, commutative property, a + b = b + a
Therefore, ^{102}/_{201 }+^{ 3}/_{4} =^{ 3}/_{4} + ^{102}/_{201}
LHS,
^{102}/_{201 }+^{ 3}/_{4 }= ^{(102×4+3×201)}/_{(201×4) }= ^{(408+603)}/_{804 }= ^{1011}/_{804}
RHS,
^{3}/_{4} + ^{102}/_{201} = ^{(102×4+201×3)}/_{(201×4)} = ^{603+408}/_{804} = ^{1011}/_{804}
Therefore, RHS = LHS, Commutative property proved.
(ii) ^{8}/_{13} , ^{23}/_{27}
Solution:
We know, commutative property, a + b = b + a
Therefore, ^{8}/_{13} + ^{23}/_{27} = ^{8}/_{13} + ^{23}/_{27} _{LHS,}
^{8}/_{13} + ^{23}/_{27} = ^{8}/_{13} + ^{[(8)x27+23×13]}/_{(13×27)} = ^{216+299}/_{351} = ^{83}/_{351}
RHS,
^{8}/_{13} + ^{23}/_{27} = ^{[23×13+(8)x27]}/_{(13×27)} = ^{299216}/_{351} = ^{83}/_{351}
Therefore, RHS = LHS, Commutative property proved.
(iii) ^{7}/_{9} , ^{18}/_{19}
Solution:
We know, commutative property, a + b = b + a
Therefore, ^{7}/_{9} + ^{18}/_{19} = ^{(18)}/_{19} + ^{(7)}/_{9}
LHS,
^{7}/_{9} + ^{18}/_{19} = ^{[(7)x19+(18)x9]}/_{(9×19)} = ^{133162}/_{171} = ^{295}/_{171}
RHS,
^{(18)}/_{19} + ^{(7)}/_{9} = ^{[(18)x9+(7)x19]}/_{(9×19)} = ^{162133}/_{171} = ^{295}/_{171}
Therefore, RHS = LHS, Commutative property proved.
 Check the commutative property of multiplication for the following pairs:
(i)^{ 22}/_{45} , ^{3}/_{4}
Solution:
We know commutative property multiplication, a×b = b×a
Therefore, ^{22}/_{45} x ^{3}/_{4} = ^{3}/_{4 }x ^{22}/_{45}
LHS,
^{22}/_{45} x ^{3}/_{4 }= ^{(22×3)}/_{(45×4)} = ^{66}/_{180}
_{RHS,}
^{3}/_{4 }x ^{22}/_{45 }= ^{(22×3)}/_{(45×4)} = ^{66}/_{180}
Therefore, RHS = LHS, Commutative property proved.
(ii) ^{7}/_{13} , ^{25}/_{27}
Solution:
We know commutative property multiplication, a×b = b×a
Therefore, ^{7}/_{13} x ^{25}/_{27} = ^{25}/_{27} x ^{7}/_{13}
LHS,
^{7}/_{13} x ^{25}/_{27} = ^{[25x(7)]}/_{27×13} = ^{175}/_{351}
RHS,
^{25}/_{27} x ^{7}/_{13} = ^{[25x(7)]}/_{27×13} = ^{175}/_{351}
Therefore, RHS = LHS, Commutative property proved.
(iii)^{ 8}/_{9}, ^{17}/_{19}
Solution:
We know commutative property multiplication, a×b = b×a
Therefore, ^{8}/_{9 }x ^{17}/_{19} = ^{17}/_{19 }x ^{(8)}/_{9}
LHS,
^{8}/_{9 }x ^{17}/_{19} = ^{(8)x17}/_{9×19} = ^{136}/_{171}
RHS,
^{17}/_{19 }x ^{(8)}/_{9 }= ^{(8)x17}/_{9×19} = ^{136}/_{171}
Therefore, RHS = LHS, Commutative property proved
 Check the distributive property for the following triples of rational numbers:
(i) ^{1}/_{8} ,^{ 1}/_{9} , ^{1}/_{10}
Solution:
We know distributive property, a (b + c) = ab + ac
Therefore, ^{1}/_{8} x (^{1}/_{9} + ^{1}/_{10}) = (^{1}/_{8} x^{ 1}/_{9}) + (^{1}/_{8} x ^{1}/_{10})
LHS,
^{1}/_{8} x (^{1}/_{9} + ^{1}/_{10}) = ^{1}/_{8} x (^{(10+9)}/_{(9×10)})
= ^{1}/_{8} x (^{19}/_{90})
= (^{19}/_{720})
RHS,
(^{1}/_{8} x^{ 1}/_{9}) + (^{1}/_{8} x ^{1}/_{10}) = (^{1}/_{9×8}) + (^{1}/_{10×8})
= (^{1}/_{72}) + (^{1}/_{40} )
=(^{1+18}/_{720}) = ^{19}/_{720}
Therefore, RHS = LHS, distributive property proved.
(ii) ^{4}/_{9} ,^{6}/_{5} ,^{11}/_{10}
Solution:
We know distributive property, a (b + c) = ab + ac
Therefore, ^{4}/_{9} x (^{6}/_{5} + ^{11}/_{10}) = (^{4}/_{9} x ^{6}/_{5} ) + (^{4}/_{9} x ^{11}/_{10})
LHS,
^{4}/_{9} x (^{6}/_{5} + ^{11}/_{10}) = ^{4}/_{9} x (^{11+12}/_{10×5}) = ^{4}/_{9} x (^{23}/_{10}) = (^{92}/_{90})
RHS,
(^{4}/_{9} x ^{6}/_{5} ) + (^{4}/_{9} x ^{11}/_{10}) = (^{24}/_{45} ) + (^{44}/_{90})= ^{(4844)}/_{90} = ^{92}/_{90}
Therefore, RHS = LHS, distributive property proved.
(iii) ^{3}/_{8} ,0 , ^{13}/_{7}
Solution:
We know distributive property, a (b + c) = ab + ac
Therefore, ^{3}/_{8} x (0 + ^{13}/_{7}) = (^{3}/_{8} x 0) + (^{3}/_{8} x^{13}/_{7})
LHS,
^{3}/_{8} x (0 + ^{13}/_{7}) = ^{3}/_{8} x (^{13}/_{7}) = ^{13×3}/_{7×8} = ^{39}/_{56}
RHS,
(^{3}/_{8} x 0) + (^{3}/_{8} x^{13}/_{7}) = ^{3}/_{8} x (^{13}/_{7}) = ^{13×3}/_{7×8} = ^{39}/_{56}
Therefore, RHS = LHS, distributive property proved.
 Find the additive inverse of each of the following numbers:
^{8}/_{5} , ^{6}/_{10}, ^{3}/_{8} , ^{16}/_{3}, ^{4}/_{1}
Solution:
Additive inverse of ^{8}/_{5} , ^{6}/_{10}, ^{3}/_{8} , ^{16}/_{3}, ^{4}/_{1} are ^{8}/_{5} , ^{6}/_{10}, ^{3}/_{8} , ^{16}/_{3}, ^{4}/_{1 }respectively.
 Find the multiplicative inverse of each of the following numbers:
2 , ^{6}/_{11}, ^{8}/_{15} , ^{19}/_{18}, ^{1}/_{1000}
Solution:
Multiplicative inverse of 2 , ^{6}/_{11}, ^{8}/_{15} , ^{19}/_{18}, ^{1}/_{1000} are ^{1}/_{2}, ^{11}/_{6} , ^{15}/_{8}, ^{18}/_{19} , 1000 respectively.
Rational Numbers – Chapter 3 – Representation of rational numbers on the Number.
Earlier, we have seen how to represent integers on a line. We choose an infinite line and fix some point on the line. This is denoted by 0. Fix a unit of length and on both sides of 0; go on marking points at equal unit distance.
We can also use the same number line to represent rational numbers.
For example,
Between any two distinct rational numbers, there is another rational number.
Rational Numbers – Chapter 3 – Exercise 1.3.4
 Represent the following rational numbers on the number line:
^{8}/_{5 }, ^{3}/_{8} , ^{2}/_{7}, ^{12}/_{5 }, ^{45}/_{13}
Solution:
^{8}/_{5}
^{3}/_{8}
^{ }
^{2}/_{7}
^{12}/_{5}
^{45}/_{13}
 Write the following rational numbers in ascending order:
^{3}/_{4} , ^{7}/_{12} ,^{ 15}/_{11} , ^{22}/_{19} ,^{ 101}/_{100} , ^{4}/_{5} ,^{ 102}/_{81} , ^{13}/_{7}
Solution:
Ascending order
^{13}/_{7} ,^{ 102}/_{81} , ^{4}/_{5} , ^{7}/_{12} ,^{ 3}/_{4}, ,^{ 101}/_{100}, ^{22}/_{19 },^{ 15}/_{11}
Method:
We know,
^{3}/_{4} , ^{7}/_{12} ,^{ 15}/_{11} , ^{22}/_{19} ,^{ 101}/_{100} , ^{4}/_{5} ,^{ 102}/_{81} , ^{13}/_{7} is equal to 0.75, 0.5, 1.3, 1.1, 1.01, 0.3, 1.8, 1.2 respectively.
 Write 5 rational number between ^{2}/_{5} and ^{3}/_{5} having the same denominators.
Solution:
We know,
^{2}/_{5} = 0.4 and ^{3}/_{5} = 0.6
Now, we have to find 5 rational numbers between 0.4 and 0.6. We get,
^{2}/_{5} = 0.4 < ^{2.1}/_{5} = 0.42 < ^{2.2}/_{5} = 0.44 < ^{2.4}/_{5} = 0.48 < ^{2.6}/_{5} = 0.52 <^{2.8}/_{5} = 0.56 < ^{3}/_{5} = 0.6
Therefore, the rational numbers between ^{2}/_{5} and ^{3}/_{5} are ^{2.1}/_{5} , ^{2.2}/_{5} , ^{2.4}/_{5} ,^{ 2.6}/_{5} and ^{2.8}/_{5}
 How many positive rational numbers less than 1 are there such that the sum of the numerator and denominator does not exceed 10?
Solution:
^{1}/_{2 },^{1}/_{3 },^{ 1}/_{4 },^{1}/_{5 },^{ 1}/_{6 },^{1}/_{7 },^{ 1}/_{8 },^{1}/_{9 },^{2}/_{3 },^{2}/_{5 },^{2}/_{7 },^{3}/_{4 },^{ 3}/_{7 },^{3}/_{5 },^{ 1}/_{2 },^{4}/_{5 },
Therefore, only 15 positive rational number are possible such that they are less than 1 and the sum of the numerator and denominator does not exceed 10.
 Suppose m/n and p/q are two positive rational numbers. Where does ^{(m+n)}/_{(n+q) }lie, with respect to m/n and p/q?
Solution:
It is given that, m/n and p/ q are 2 numbers.
If ^{m}/_{n }= ^{p}/_{q }i.e., if ^{m}/_{n }= ^{p}/_{q }=^{1}/_{2 }
Then,
^{(m+n)}/_{(n+q)} = ^{(1+1)}/_{(2+2)} = ^{2}/_{4} = ^{1}/_{2}
Therefore, if ^{m}/_{n }= ^{p}/_{q then }^{(m+n)}/_{(n+q) }=^{ m}/_{n }= ^{p}/_{q}
If ^{m}/_{n }and ^{p}/_{q }are 2 distinct numbers. i.e., ^{m}/_{n }= ^{1}/_{5 }and ^{p}/_{q }= ^{1}/_{3 }then,
^{(m+n)}/_{(n+q)} = ^{(1+1)}/_{(5+3)} = ^{(2)}/_{(8)} = ^{1}/_{4}
Therefore, if ^{m}/_{n }and ^{p}/_{q }are 2 distinct numbers then ^{(m+n)}/_{(n+q) }lies between ^{m}/_{n }and ^{p}/_{q }
i.e,
 How many rational numbers are there strictly between 0 and 1 such that the denominator of the rational number is 80?
Solution:
^{1}/_{80} , ^{2}/_{80} , ^{3}/_{80} , ^{4}/_{80} … ^{78}/_{80} , ^{79}/_{80}
Therefore, there are 79 positive rational numbers.
 How many rational numbers are there strictly between 0 and 1 with the property that the sum of the numerator and denominator is 70?
Solution:
^{1}/_{69} , ^{2}/_{68} , ^{3}/_{67} , ^{4}/_{66} … ^{68}/_{2} , ^{69}/_{1}
Therefore, there are 69 rational numbers.
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