- Find:
(i) 641/2
(ii)321/5
(iii) 1251/3
Solution:
(i) 641/2 = (82)1/2 = 82*(1/2) = 8
(ii)321/5 = (25)1/5= 25*(1/5) = 2
(iii) 1251/3 = (53)1/3 = 53*(1/3) = 5
- Find
(i)93/2
(ii) 322/5
(iii) 163/4
(iv) 125-1/3
Solution:
(i)93/2 = (91/2)3 = 33 = 9
(ii) 322/5 = (321/5)2 = 22 = 4
(iii) 163/4 = (161/4)3 = (2)3 = 8
(iv) 125-1/3 = (1251/3)-1 = 5-1 = 1/5
- Simplify:
(i)22/3.21/5
(ii) (1/33)7
(iii) 111/2/111/4
(iv)71/2. 81/2
Solution:
(i)22/3.21/5 = 22/3 + 1/5 = 210+3/15 = 213/15
(ii) (1/33)7 = (3-3)7 = 3-21
(iii) 111/2/111/4 = 111/2 – 1/4 = 112-1/4 = 111/4
(iv)71/2. 81/2 = 561/2
2 thoughts on “Number System – Exercise 1.6 – Class IX”
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