**Previous exercise – Statistics – Exercise 6.2 – Class X**

#### Statistics – Exercise 6.3

Draw pie charts to represent the following data.

- The number of students who are willing to join their favorite sports.

Name o the sport | foot ball | tennis | volley ball | hockey | basket ball | other |

Number of students | 35 | 14 | 10 | 6 | 5 | 1 |

- The survey carried out in the class regarding places of visit for excursion and the number of students who opted each place.

Places | mysuru | vijaypura | gokarna | Chitradurga |

Number of students | 14 | 6 | 2 | 18 |

- A survey was conducted to study the various brands of soaps used by people in a village

Brand of soap | A | B | C | D |

Percent of villagers | 50% | 30% | 15% | 5% |

II. Study the pie charts given below and answer the questions in each case.

- The given pie chart shows the annual agricultural yield f a certain place. If the total production is 8100 tons.

Answer the following questions

(i)What is the yield in tons of rice, ragi, sugar cane and others

(ii) How much percent do the production of ragi exceeds that of rice?

(iii) If the yield of sugarcane on a different year was 2400 tons, find the yield of rice?

- A group of people were interviewed and asked which TV channel they liked the most. The results are shown in the pie chart

Answer the questions.

(i) What fraction of the people who were interviewed watched

(a)Channel 3

(b) channel 5

© channel 1

(d) channel 2

(e) channel 9

(ii) If there were 200 people, how many viewed each of the channels

#### Statistics – Exercise 6.3 – Solution:

Draw pie charts to represent the following data.

- The number of students who are willing to join their favorite sports.

Name o the sport | foot ball | tennis | volley ball | hockey | basket ball | other |

Number of students | 35 | 14 | 10 | 6 | 5 | 1 |

Solution:

- The survey carried out in the class regarding places of visit for excursion and the number of students who opted each place.

Places | mysuru | vijaypura | gokarna | Chitradurga |

Number of students | 14 | 6 | 2 | 18 |

Solution:

- A survey was conducted to study the various brands of soaps used by people in a village

Brand of soap | A | B | C | D |

Percent of villagers | 50% | 30% | 15% | 5% |

Solution:

**II. Study the pie charts given below and answer the questions in each case.**

**The given pie chart shows the annual agricultural yield f a certain place. If the total production is 8100 tons.**

**Answer the following questions**

**(i)What is the yield in tons of rice, ragi, sugar cane and others**

**(ii) How much percent do the production of ragi exceeds that of rice?**

**(iii) If the yield of sugarcane on a different year was 2400 tons, find the yield of rice?**

Solution:

(i) Given: total production = 8100 tons

Total yield in degrees = 360˚

Rice production in tons = ^{8100 x 40}/_{360 }= 900

Ragi production in tons = ^{8100 x 100}/_{360 }= 2250

Sugar cane production in tons = ^{8100 x 80}/_{360 }= 1800

Other productions in tons = ^{8100 x 140}/_{360 }= 3150

(ii)

Production of ragi in percentage = ^{100 x 100}/_{360} = 27.78%

Production of rice in percentage = ^{100 x 40}/_{360} = 11.11%

16.67% exceeds the production of ragi that of rice.

(iii)

Sugar cane production in tons in the current year = ^{8100 x 80}/_{360 }= 1800 tons.

Yield of sugarcane on a different year = 2400 tons

Rice production in tons = ^{8100 x 40}/_{360 }= 900

Therefore, the production of rice in the different = ^{900 x 2400}/_{1800} = 1200 tons.

**A group of people were interviewed and asked which TV channel they liked the most. The results are shown in the pie chart**

**Answer the questions.**

**(i) What fraction of the people who were interviewed watched**

**(a)Channel 3**

**(b) channel 5**

**© channel 1**

**(d) channel 2**

**(e) channel 9**

**(ii). If there were 200 people, how many viewed each of the channels**

Solution:

**(i) The fraction of the people who were interviewed watched**

(a)Channel 3 = ^{45˚}/_{360˚} = ^{1}/_{8}

(b) channel 5 = ^{27˚}/_{360˚} = ^{3}/_{40}

© channel 1 = ^{108˚}/_{360˚} = ^{3}/_{10}

(d) channel 2 = ^{90˚}/_{360˚} = ^{1}/_{4}

(e) channel 9 = ^{90˚}/_{360˚} = ^{1}/_{4}

**(ii) If there were 200 people, how many viewed each of the channels.**

(a)No. of people viewed Channel 3 out of 200 people = ^{45˚}/_{360˚} x 200 = 25

(b) No. of people viewed Channel 5 out of 200 people = ^{27˚}/_{360˚} x 200 = 15

© No. of people viewed Channel 1 out of 200 people = ^{108˚}/_{360˚} x 200 = 60

(d) No. of people viewed Channel 2 out of 200 people = ^{90˚}/_{360˚} x 200 = 50

(e) No. of people viewed Channel 9 out of 200 people = ^{90˚}/_{360˚} x 200 = 50